x^2=2(6x+4)

Solution for x^2=2(6x+4) equation:

x^2=2(6x+4)

We move all terms to the left:

x^2-(2(6x+4))=0


We calculate terms in parentheses: -(2(6x+4)), so:

2(6x+4)

We multiply parentheses

12x+8

Back to the equation:

-(12x+8)


We get rid of parentheses

x^2-12x-8=0

a = 1; b = -12; c = -8;
Δ = b2-4ac
Δ = -122-4·1·(-8)
Δ = 176
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{176}=\sqrt{16*11}=\sqrt{16}*\sqrt{11}=4\sqrt{11}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-4\sqrt{11}}{2*1}=\frac{12-4\sqrt{11}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+4\sqrt{11}}{2*1}=\frac{12+4\sqrt{11}}{2}
$